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標題:
發問:
solve the equation 2i+(3+i)z=5-8i
最佳解答:
2i + (3 + i)z = 5 - 8i (3 + i)z = 5 - 8i - 2i = 5(1 - 2i) z = 5(1 - 2i)/(3 + i) z = 5(1 - 2i)(3 - i) / [(3 + i)(3 - i)] = 5[3 - 7i + 2i2] / (32 - i2) = 5(3 - 7i - 2) / (9 + 1) = 1/2 - 7/2 i 2009-09-15 11:42:44 補充： i^2 = -1
其他解答:
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中4數學(十萬火急)發問:
solve the equation 2i+(3+i)z=5-8i
最佳解答:
2i + (3 + i)z = 5 - 8i (3 + i)z = 5 - 8i - 2i = 5(1 - 2i) z = 5(1 - 2i)/(3 + i) z = 5(1 - 2i)(3 - i) / [(3 + i)(3 - i)] = 5[3 - 7i + 2i2] / (32 - i2) = 5(3 - 7i - 2) / (9 + 1) = 1/2 - 7/2 i 2009-09-15 11:42:44 補充： i^2 = -1
其他解答:
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