標題:
三角問題(sinθ tanθ cosθ)
發問:
最佳解答:
0 θ 360 0 3θ 1080 6 3θ + 6 1086 當tan(3θ + 6) = 1 3θ + 6= 45, 225, 405, 585, 765, 945 3θ = 39, 219, 399, 579, 759, 939 θ = 13, 73, 133, 193, 253, 313 當2sinθ = tanθ 2sinθ = sinθ/cosθ 2sinθcosθ = sinθ 2sinθcosθ - sinθ = 0 sinθ(2cosθ - 1) = 0 sinθ = 0or cosθ = 1/2 θ = 0, 180, 360or θ = 60, 300 θ = 0, 60, 180, 300, 360
其他解答:4E350C6F99F7EF4C
三角問題(sinθ tanθ cosθ)
發問:
此文章來自奇摩知識+如有不便請留言告知
tanθ [0 θ 360] (全部都是度數) 當tan(3θ+6)=1 解有6個 分別是13,73,133,193,253,313 當2sinθ=tanθ 解有5個 分別是0,60,180,300,360 對於這些要如何以式表達出那些個解? 請列明步驟,thx最佳解答:
0 θ 360 0 3θ 1080 6 3θ + 6 1086 當tan(3θ + 6) = 1 3θ + 6= 45, 225, 405, 585, 765, 945 3θ = 39, 219, 399, 579, 759, 939 θ = 13, 73, 133, 193, 253, 313 當2sinθ = tanθ 2sinθ = sinθ/cosθ 2sinθcosθ = sinθ 2sinθcosθ - sinθ = 0 sinθ(2cosθ - 1) = 0 sinθ = 0or cosθ = 1/2 θ = 0, 180, 360or θ = 60, 300 θ = 0, 60, 180, 300, 360
其他解答:4E350C6F99F7EF4C
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