close
標題:
Basicity of an acid (X)
3. 10.0 cm3 of a 1.20 M unknown acid X was diluted to 100.0 cm3. 25.0 cm3 of the diluted X required 18.0 cm3 of 0.50 M sodium hydroxide solution for complete neutrallization. Calculate the basicity of acid X. 請列明計算步驟。THX~ -V-""
最佳解答:
Number of mole of acid X in the given solution = molarity X volume = 1.20 X 10.0 / 1000 = 0.012 mol So, in 100.0 cm3 of the diluted solution, there is 0.012 mol of acid X. So, number of mole of acid X in 25.0 cm3 diluted solution = 0.012 X 25.0 / 100 = 3 X 10-3 mol Number of mole of sodium hydroxide reacted = molarity X volume = 0.50 X 18.0 / 1000 = 9 X 10-3 mol Therefore, molar ratio of acid X to sodium hydroxide solution = 3 X 10-3 : 9 X 10-3 = 1 : 3 Assume only H+ ions in acid X reacts with NaOH. So, the basicity of acid X is 3. X is a tribasic acid.
其他解答:
Basicity of an acid (X)
此文章來自奇摩知識+如有不便請留言告知
發問:3. 10.0 cm3 of a 1.20 M unknown acid X was diluted to 100.0 cm3. 25.0 cm3 of the diluted X required 18.0 cm3 of 0.50 M sodium hydroxide solution for complete neutrallization. Calculate the basicity of acid X. 請列明計算步驟。THX~ -V-""
最佳解答:
Number of mole of acid X in the given solution = molarity X volume = 1.20 X 10.0 / 1000 = 0.012 mol So, in 100.0 cm3 of the diluted solution, there is 0.012 mol of acid X. So, number of mole of acid X in 25.0 cm3 diluted solution = 0.012 X 25.0 / 100 = 3 X 10-3 mol Number of mole of sodium hydroxide reacted = molarity X volume = 0.50 X 18.0 / 1000 = 9 X 10-3 mol Therefore, molar ratio of acid X to sodium hydroxide solution = 3 X 10-3 : 9 X 10-3 = 1 : 3 Assume only H+ ions in acid X reacts with NaOH. So, the basicity of acid X is 3. X is a tribasic acid.
其他解答:
文章標籤
全站熱搜
留言列表
